320-104x-6x^2=0

Solution for 320-104x-6x^2=0 equation:

320-104x-6x^2=0

a = -6; b = -104; c = +320;
Δ = b2-4ac
Δ = -1042-4·(-6)·320
Δ = 18496
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{18496}=136$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-104)-136}{2*-6}=\frac{-32}{-12}
=2+2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-104)+136}{2*-6}=\frac{240}{-12}
=-20
$